LeetCode[202] Happy Number
1. 題目
Write an algorithm to determine if a number is “happy”.
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example:
Input: 19
Output: true
Explanation:
- 1 * 1 + 9 * 9 = 82
- 8 * 8 + 2 * 2 = 68
- 6 * 6 + 8 * 8 = 100
- 1 * 1 + 0 * 0 + 0 * 0 = 1
2. 思路
因為不是Happy number的話會進入迴圈 (loops endlessly in a cycle) 所以可想到 floyd’s cycle detection
3.解題
int check_happy(int target)
{
int sum = (target % 10)*(target % 10);
/* Chech digit */
while ((target / 10) > 0) {
target /= 10;
sum += (target % 10)*(target % 10);
}
return sum;
}
bool isHappy(int n)
{
int fast = n, slow = n;
do {
/* slow calculate once per round*/
slow = check_happy(slow);
/* fast calculate two times per round*/
fast = check_happy(fast);
fast = check_happy(fast);
if (slow == 1 || fast == 1)
return true;
} while (slow != fast);
return false;
}
本部落格所有文章除特別聲明外,均採用 CC BY-NC-SA 4.0 許可協議。轉載請註明來自 LuYee6813's Blog | 技術分享!